At t =0 the current to a dc electric motor is reversed, resulting in an angular

Question

At t=0 the current to a dc electric motor is reversed, resulting in an angular displacement of the motor shaft given by(t)=( 257 rad/s )t( 19.3 rad/s2 )t2( 1.45 rad/s3 )t3.

A.At what time is the angular velocity of the motor shaft zero?

B. Calculate the angular acceleration at the instant that the motor shaft has zero angular velocity.

C. How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero?

D. How fast was the motor shaft rotating at t=0, when the current was reversed?

E. Calculate the average angular velocity for the time period from t=0 to the time calculated in part A.

Explanation / Answer

A) theta(t) = 257t - 19.3t^2 - 1.45t^3

w = d(theta) / dt = 257 - 38.6t - 4.35t^2 = 0

4.35t^2 + 38.6t - 257 = 0

t = 4.44 sec

B)

alpha = dw/dt = -38.6 - 8.7t

at t = 4.44s

alpha = -38.6 - 8.7(4.44) = - 77.23 rad/s^2

C)

theta = (257 x 4.44) - (19.3 x 4.44^2) - (1.45 x 4.44^3)

= 633.69 rad

revolutions = 633.19 / 2pi = 100.9 revolutions

d) w = 257 - 38.6t - 4.35t^2 =

at t- 0

w = 257 rad/s

E) avergae angular velocity = theta / t = 633.69/4.44 = 142.72 rad/s

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