A small object is placed to the left of a convex lens and on its optical axis. T

Question

A small object is placed to the left of a convex lens and on its optical axis. The object is 30 cm from the lens, which has a focal length of 46 cm. If the object is moved to a position 55 cm to the left of the lens, what will the image position be? (A positive value for p, or position, means the image is on the right side of the lens.) p = cm Describe the nature of this new image. (Select all that apply.) virtual real upright inverted enlarged reduced on the left side of the lens on the right side of the lens

Explanation / Answer

From thin lenses equation
1/f = 1/do + 1/di
the image distance is
di = (f * do) / (do - f) = (46 * 55) / (55 - 46) = 281.11 cm

So, p = 281.11 cm

p > 0, so the image is on the right side of the lense.

Further, image shall be real.

From magnification formula
M = - I/O = - di/do
we obtain
M = -281.11/55 = -5.11

-ve value of M means image is real and inverted.

Further, value of M is greater than 1, so the image shall be enlarged.

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