A rectangular summing pool is 4 feet deep, 75 feet long, and 25 feel wide If is
ID: 1447700 • Letter: A
Question
A rectangular summing pool is 4 feet deep, 75 feet long, and 25 feel wide If is completely filled with water What is the hydrostatic twee on the bottom of the poof? What is the hydrostatic force on the shorter wall of the poof? What is the hydrostatic force on the longer wall of the pool' how much worn e required to pump all the water out of the pool (i e. up to the top of the A, dam has the shape of an isosceles trapezia it is 40 feet deep its base is 30 feet long while on the surface ft measures 60 feet across (its thickness is irrelevant to the- problem) if the water reaches the fop of the dam what is the total force on the face of the dam?Explanation / Answer
Ans:-
A ] hydrostatic force on bottom
1ft = 0.3048
F = mg = Vg = 0.998*10^3 *1.22*22.86*7.62*9.8 =20.78*10^5N
B] shorter wall
Pressure = F /A=20.78*10^5/22.86*7.62= 1.19*10^4N/m^2
F = P*A = 1.19*10^4 *7.62*1.22 =110627.16
F = f/2 =5.5*10^4N
C] long side
F = p*A =1.19*10^4*22.86*7.62 =2072899.08/2 = 1.04*10^6
D]W= F*d= 20.78*10^5 * 1.22 = 2.5*10^6 J
Que 2
Ans: - from fig
2x + 9.14=18.29
X=4.57m
a /x = 12.19-h /12.19
a/4.57 = 12.19-h/12.19
a= 4.57-0.3749h
l= 2a + 9.14 = 2*(4.57-0.3749h)+9.14 =18.28 – 0.7498h
Aslice = l*h= (18.28-0.7498h)*h
F= P *A = 1.01*10^5*h(18.28-0.7498h)*h
F = integration (1.01*10^5*h(18.28-0.7498h)*h)from 0 to12.19
F = ................N
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