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Homework 9: Chapter 25 Problem 1 (see Sectiou 25.3) 1 A) What is the magnetic fl

ID: 1448346 • Letter: H

Question

Homework 9: Chapter 25 Problem 1 (see Sectiou 25.3) 1 A) What is the magnetic flux through the loop shown in the figure? 10 cm B) If both magnetic fields begin to decrease in magnitude, what is the direction of the induced current in the loop? Explain with Lenz Law. Problem 2 (see Section 25.3) The figures shows a 100-turn coil of wire ofradius 12 cm in a 0.15Tmagnetic field. The coil is rotated 900 in 0.30 s, ending up parallel to the field. What is the average emfinducedin the coil asitrotates? Prepare) Solve) Assess) (How does the induced emf change if the time is halved to 0.15 s?

Explanation / Answer

magnetic flux = = BA

here flux = (B1A1 - B2A2)

flux = (2-1) * 0.2 * 0.2

flux = 0.04 Wb
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accroding to lenz law, induced current always opposes the cause of its moiton

so as here since B into board is more , to this it opposes

so direction of emf is counter clockwise
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induced emf is defiend as the rate of change of magnetic flux

in mathematical form,

induced emf e = NAdB/dt or NABW

where A = area

N = no. of tunrs

W = angular frequency

dB/dt = rate of change of amgnetic flux

so

emf e = 100 * 3.14 * 0.12 * 0.12 * 0.15/0.3

emf e = 2.26 Volts

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if time is 0.15 secs

emf e = 100 * 3.14 * 0.12 * 0.12 * 0.15/0.15

emf e = 4.52 Volts