The values of the components in the circuit are L-210 mH, R1-410 R2-200 , and -1

Question

The values of the components in the circuit are L-210 mH, R1-410 R2-200 , and -100. Use downward as the positive direction for all currents. Find RI (a) immediately after the switch is closed (after being open a long time) ...the current through the inductor er being open a long time). mA ...the current through R2 MA (b) a long time after the switch has been closed.. the current through the inductor mA ..the current through R2 MA (c) immediately after the switch is open (after being closed a long time) ...the current through the inductor mA

Explanation / Answer

(A)
When switch is Closed, Inductor will act as an open circuit, i,e No Current will flow through the inductor.
(1)
IL = 0 A
(2)
Current Through R2, = e/(R1 + R2)
I2 = 10.0/(410 + 200)
I2 = 16.4 mA

(b)
When switch is Closed for a long time, Inductor will act as a short circuit, i,e All the Current will flow through the inductor.

(1)
IL = e/R1 = 10.0/410
IL = 24.4 mA

(2)
As all the current will flow through Inductor, Current through R2 = 0
I2 = 0

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