The values of the components in the circuit are L = 270 mH, R1 = 270 ?, R2 = 240
ID: 2031690 • Letter: T
Question
The values of the components in the circuit are L = 270 mH, R1 = 270 ?, R2 = 240 ?, and ? = 10.0 v. Use downward as the p ositive direction for all currents. Find... Ri N. (a) immediately after the switch is closed (after being open a long time)... ...the current through the inductor ...the current through R2 12 mA (b) a long time after the switch has been closed ...the current through the inductor MA ..the current through R2 12 = 10 MA (c) immediately after the switch is open (after being closed a long time)... ...the current through the inductor MA ...the current through R2 (d) a time 1.238e-03 s after the switch is open.... ...the current through the inductor iTA ...the current through R2 mAExplanation / Answer
a) IL = 0 <<<<<<<<----------------------Answer
I2 = V/(R1+R2)
= 10/(270 + 240)
= 19.6 mA <<<<<<<<----------------------Answer
b)
IL = V/R1
= 10/270
= 37.0 mA <<<<<<<<----------------------Answer
I2 = 0 mA <<<<<<<<----------------------Answer
c) IL = 37.0 mA <<<<<<<<----------------------Answer
I2 = 37.0 mA <<<<<<<<----------------------Answer
d) Time constant when switch is open,
T = L/R2
= 0.270/240
= 1.125*10^-3 s
at time t = 1.238*10^-3 s
IL = Imax*e^(-t/T)
= 37*e^(-1.238/1.125)
= 12.3 mA <<<<<<<<----------------------Answer
I2 = IL
= 12.3 mA <<<<<<<<----------------------Answer
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