Two wires carry equal currents in opposite directions, as w. The field is 2.0 at

Question

Two wires carry equal currents in opposite directions, as w. The field is 2.0 at a point below the lower wire. The distance between the wires is twice the distance between this point and the lower wire. What is the direction of the field at point 1 (midway between the two wires)? What is the strength of the field at point 1? Express your answer with the appropriate units. What is the direction of the field at point 2 (the same distance above the upper wire as the 2.0 ¦t point is below the lower wire)? What is the strength of the field at point 2? Express your answer with the appropriate units.

Explanation / Answer

Let analyze the point where the magnetic fiueld is 2 mT
this is at a distance d from bototm wire and at a distance 3d from top wire
B = miuo*I /2*Pi (1/d1 - 1/d2)
2 = miuo*I /2*Pi (1/d - 1/3d)
2 = miuo*I /2*Pi ((3-1)/3d)
2 = miuo*I*2 /6*Pi*d
miuo*I/2*pi*d =3 mT

A)
Field due to top wire = into the page
Field due to bottom wire = into the page
AnsweR: into the page

B)
Bnet = miuo*I / (2*pi*d) + miuo*I / (2*pi*d)
= 3+ 3
= 6 mT
Answer: 6 mT

C)
point 2 is symmetric to point where 2 mT field exist
So field over there will also be same
Answer: out of the page

D)
Answer: 2 mT

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