Two wires carry currents to the right, where l1 63.65 A and 12-79.53 A. A negati

Question

Two wires carry currents to the right, where l1 63.65 A and 12-79.53 A. A negatively charged particle, with charge-72 C is moving to the right with velocity 6.21x106 m/s The wires are a distance d = 4.52x 10.3 m apart and the charge is a distance y 0.51x10. 3 m from current l1 What is the total magnetic force on the charge? Forces that are up (towards l2) are positive and forces that are down (towards 11) are negative. Give your answer in Newtons to at least three significant figures to avoid being counted incorrect due to rounding. y. I1

Explanation / Answer

in between the conductors,the magnetic field is in opposite direction

field at -q due to I2 is B2 = mu_o*I2/(2*pi*(d-y)) = (4*3.141*10^-7*79.53)/(2*3.142*(4.52*10^-3 - 0.51*10^-3)) = 0.00396 T into the page

field at -q due to I1 is B1 = (mu_o*I1)/(2*pi*y) = (4*3.142*10^-7*63.65)/(2*3.142*0.51*10^-3) = 0.0249 T out of the page

Net field at -q is Bnet = B1-B2 = 0.0249-0.00396 = 0.02094 T out of the page

magnetic force is F = q*V*B = (72*10^-6*6.21*10^6*0.02094) = 9.36 N

direction is towards I2

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