Two wires carry currents to the right, where I_1 = 65 A and I_2 = 120 A. A negat
ID: 1997938 • Letter: T
Question
Two wires carry currents to the right, where I_1 = 65 A and I_2 = 120 A. A negatively charged particle, with charge -45 mu C moving to the right with velocity 5.7 times 10^6 m/s. The wires are a distance d = 5.5 times 10^-3 m apart and the charge is a distance y = 2.0 times 10^-3 m from current I_1. What is the total magnetic force on the charge? Forces that are up (towards I_2) are positive and forces that are down (towards I_1) are negative. Give your answer in Newtons to at least three significant figures to avoid being counted incorrect due to rounding.Explanation / Answer
Here ,
I1 = 65 A
I2 = 120 A
magnetic field at the location of charged , B = u0 * (I2 - I1)/(2 * pi * d)
B = 4pi *10^-7* (120 - 65)/(2pi * 5.5*10^-3/2)
B = 0.004 T
total magnetic force on the charge = B*I*L
total magnetic force on the charge = 0.004 * 5.7 *10^6 * 45 *10^-6
total magnetic force on the charge = 1.03 N
the total magnetic force on the charge is 1.03 N
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