What is the force acting on it due to its motion in the field? Use a positive or

Question

What is the force acting on it due to its motion in the field? Use a positive or negative value to indicate a force directed up or down the page, respectively. N A proton is moving at 2.00times10^5 m/s and begins to circle at a radius of 0.0065 m. What is the strength of the perpendicular magnetic field acting on the proton? T A proton travels with a speed of 8.34times10^5 m/s at an angle of 32.3degree with the direction of a magnetic field. The field exerts a force of 3.00times10^-17 N on the proton. What is the strength of the field? T

Explanation / Answer

use,
magnetic force = centrepetal force
q*v*B = m*v^2/r
B = m*v/q*r
= (1.673*10^-27)*(2*10^5) / (1.6*10^-19*0.0065)
= 0.322 T

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