What is the force acting on this satellite? Answer in units of N 025 (part 2 of

Question

What is the force acting on this satellite? Answer in units of N 025 (part 2 of 2) 10.0 points What is the mass of this planet? Answer in units of kg. 024 (part 1 of 2) 10.0 points 211.2 Given: G = 6.67259 × 10-11 N m2/kg A 1380 kg geosynchronous satellite or- bits a planet similar to Earth at a radius 1.95 x 105 km from the planet's center. Its angular speed at this radius is the same as the rotational speed of the Earth, and so they ap pear stationary in the sky. That is, the period of the satellite is 24 h

Explanation / Answer

w = 2pi / T = 2 pi / (24 x 3600 s)

w = 7.272 x 10^-5 rad/s

(A)Force = m w^2 r

r = (1.95 x 10^8) m

F = (1380)(7.272 x 10^-5)^2 (1.95 x 10^8)

F = 1423 N

(B) F = G M m / r^2

1423 = (6.67 x 10^-11)(M) (1380) / (1.95 x 10^8)^2

M = 5.88 x 10^26 kg

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