The figure shows a simple RC circuit R = 2.0 times 10^5 Ohm and the voltage acro

Question

The figure shows a simple RC circuit R = 2.0 times 10^5 Ohm and the voltage across the capacitor is initially V_0 = 100V, at t = 0, the switch is closed. Answer the following questions according to the following equations. tau = RC; q_0 = C V_0; q(t) = Q_0e^t/RC; V_C(t) = V_0e^t/RC a) What is the time constant of this circuit? b) What is the initial charge in the capacitor before closing the switch? c) What is the charge in the capacitor after 1 s? d) What is the voltage across the capacitor after 1s?

Explanation / Answer

a) Time constant = RC = 2 x 10^5 x 10 x 10^-6 = 2 s

b) initial charge = C V = 10 x 10^-6 x 100 = 10^-3 C

c) Q = (10-3)*e-0.5

d) V(1) = 100*e-0.5

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