In the picture below, the two wires carry current i1 and i2, respectively, with

Question

In the picture below, the two wires carry current i1 and i2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right.

If i1 = i2, then the wires are attracted to each other.
If v = 0, then the force on q is zero.
If i2 = 0 and i1 is greater than zero, then the magnetic field near charge q points out of the page.
If i2 = 0 and i1 is greater than zero, then the force on q points into the page.
If i1 is greater than i2, then the force on q is north.

If i2 = - i1 then the force on q equals zero.

If i2 = 0 and i1 is greater than zero, then the force on q is north.

Explanation / Answer

if i1 = i2 :

if currents are in same direction, then they will attract each other. (True)

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magnetic force , Fm = q(v x B)

if v= 0 then F = 0

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from right hand rule,

B due to i1 = into the page

False
----------------

due to i1 , B = into page

B = q ( v x B)

v is to the right

then force = upwrad

False

------------

this same as we got in upper part.

F = upward ( to the north )

True

------------------

if i1 = i2 then magnitude will be same but direction will be opposite .

hence Bnet = B1- B2 = 0

F = = q ( v x B) = 0

True

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then it will in same as we disscussed above,

B1 > B2

Bnet = B1- B2 > 0 into the page

hence F = upward (north )

True

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