In the picture below, the two wires carry current i1 and i2, respectively, with

Question

In the picture below, the two wires carry current i1 and i2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right.

If i2 = 0 and i1 is greater than zero, then the magnetic field near charge q points out of the page.

If i2 = 0 and i1 is greater than zero, then the force on q points into the page.

If i1 = i2, then the wires are attracted to each other.

If v = 0, then the force on q is zero.

If i2 = - i1 then the force on q equals zero.

If i1 is greater than i2, then the force on q is north.

If i1 = 0 and i2 is greater than zero then the force on q is south.

Explanation / Answer

1) If i2 = 0 and i1 is greater than zero, then the magnetic field near charge q points out of the page. (FALSE)

according to right hand rule, point thumb in the direction of current and the direction of your right hand will give you magnetic field.

2) If i2 = 0 and i1 is greater than zero, then the force on q points into the page. (FALSE)

force = q. VX B so force would be upward

3) If i1 = i2, then the wires are attracted to each other. (TRUE)

force = BIL

4) If v = 0, then the force on q is zero. (TRUE)

5) If i2 = - i1 then the force on q equals zero. (FALSE)

force due to both wires will get add up.

6) If i1 is greater than i2, then the force on q is north. (TRUE)

same as part 2

7) If i1 = 0 and i2 is greater than zero then the force on q is south. (TRUE)

opposite of part 6

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