C When Five Capacitors Wit... X NI Home I Portal X v Arkansas State University,

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C When Five Capacitors Wit... X NI Home I Portal X v Arkansas State University, X Y pcv13 shot or nasal Ya... X vaccines: VPD-VAC/Pneu... X ii wwww.saplinglearning.com/ibiscms/mod/ibis/view.php?id 2471970 e a Search Sapling earning When five capacitors with equal capacitances are connected in series, the equivalent capacitance of the combination is 2.09 mF. The capacitors are then reconnected so that a parallel combination of two capacitors is connected in series with a parallel combination of three capacitors. Calculate the equivalent capacitance of this combination. Enter your result in the unit of millifarad Number mF Tools x 10 4x 4:32 PM 3/31/2016 Search the web and Windows

Explanation / Answer

when capacitors are connected in series

1/C = 1/C1+1/C2 + 1/C3 + 1/C4 + 1/C5

1/C = 5/C1

C = C1/5 = 2.09*10^-3 F

C1 = 0.01045 F

now,

in another connection two of capacitors are connected in parallel

C ' = C1+C2 = 2C1 = 2*0.01045 = 0.0209 F

three of capacitors are connected in parallel

C" = C3+C4+C5 = 3*0.01045 = 0.03135 F

now, C' and C" are connected in series

C = C'C"/(C'+C") = 0.0209*0.03135/(0.0209+0.03135) = 0.01254 = 12.54 mF

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