The figure below is a cross-sectional view of a coaxial cable. The center conduc

Question

The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, which is surrounded by an outer conductor, which is surrounded by another rubber layer. In a particular application, the current in the inner conductor is I_2 = 1.06 A out of the monitor, and the current in the outer conductor is I_2 = 2.84 A into the monitor. Determine the magnitude and direction of the magnetic field at point a. A mu T Determine the magnitude and direction of the magnetic field at point b. A mu T

Explanation / Answer

a:

B = uI1/2pira

=2x10^-7(1.06/0.001

=2.12x10^-4 T

=212 uT

direction clockwise

b:

B = u0(I1-I2)/(2pirb) = 2*10^-4* (2.84-1.06)/0.003 = 1.19x10^-4 T

=119 uT

direction counterclockwise

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