?Unpolarized light whose intensity is 1.83 W/m2 is incident on the polarizer in

Question

?Unpolarized light whose intensity is 1.83 W/m2 is incident on the polarizer in the drawing. (a) What is the intensity of the light leaving the polarizer? (b) If the analyzer is set at an angle of = 53.0° with respect to the polarizer, what is the intensity of the light that reaches the photocell?

Chapter 24, Problem 39 Unpolarized light whose intensity is 1.83 W/m2 is incident on the polarizer in the drawing. (a) What is the intensity of the light leaving the polarize? (b) If the analyzer is set at an angle org 53.0° with respect to the polarizer, what is the intensity of the light that reaches the photocell? Ecos Polarizer Photocell Unpolarized light Analyzer 90° E cos (a) Number Units (b) Number Units

Explanation / Answer

Unpolarized light at intensity I0 = 1.83 W/m^2 enters the 1st polarizer. In this situation the polarized light has 1/2 the ave. intensity of the incident light

Ave. intensity of light leaving the 1st polarizer I1 = I0/2 = 0.915 W/m^2

Intensity of light leaving the 2nd polarizer is I1*cos^2(53 deg) = 0.3314 W/m^2

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