The figure shows a long straight wire that just touches a loop carrying a curren

Question

The figure shows a long straight wire that just touches a loop carrying a current I_1. Both lie in the same plane. In what direction must the current I_2 flow in the straight wire in order to create a field at the center of the loop in the direction opposite to that created by the loop? What is the ratio I_1/I_2 that gives zero field strength at the center of the loop, in terms of the variables given in the problem statement? What is the direction of the field directly above the loop in this circumstance? (above the loop here means out of the page, in the z-direction).

Explanation / Answer

A) magnetic field due to circular loop is out of the page ,where as due to straight wire the field at the center of the loop must be into the page ,then

to create such field at the center of the loop by the straight wire,the direction of I2 must be left

B) B1/B2 =[mu_o*i1/(2*R)] / (mu_0*i2/(2*pi*R)

1 = i1/(i2/pi) = pi*(i1/i2)

i1/i2 = 1/pi

C) into the page

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