The figure shows the orientation of a rectangular loop consisting of 80 closely

Question

The figure shows the orientation of a rectangular loop consisting of 80 closely wrapped terms each carrying a current I. The magnetic field in the region in the region in (40I) mT. The loop can turn about the y axis. If theta = 30 degree, a = 0.40 m, b = 0.30 m, and I = 8.0 A, what is the magnitude of the torque exerted on the loop? Ans: 2.7 N middot m A wire (mass - 50 g, length = 40 cm) is suspected horizontally by two vertical wires which conduct a current I = 8.0 A, as shown in the figure. The magnetic field in the region is into the paper and has a magnitude of 60 mT. What is the tension in either wire? Ans : 0.34 N A charged particle (m = 5.0 g, q = -70 mu C) moves horizontally at a constand speed of 30 km/s in a region where the fire fall gravitational acceleration is 9.8 m/s downward, the electric field is 700 NC upward, and the magnetic field is perpendicular to the velocity of the particle. What is the magnitude of the magnetic field in this region? Ans : 47 mT An electron follows a circular path (radius = 15 cm) in a uniform magnetic field (magnitude = 3.0 G). What is the period of this motion? Ans 0.12 mu s A proton with a kinetic energy of 0.20 keV follows a circular path in a region where the magnetic field is uniform and has a magnitude of 60 mT. What is the radius of this path? Ans : 3.4 cm A protein in accelerated from rest through a potential difference of 150 V. It them counter a region of uniform magnetic field and moves in a circular path (radius = 12 cm). What is magnitude of the magnetic field in this region? Ans : 15 mT

Explanation / Answer

Solving 13th question

torque = NIABsin(theta)

where

N is number of turns =80

I is current =8 A

A is area of loop=0.3*0.4=0.12 m^2

B is magnetic field=40i *10^(-3) T

theta is angle between area vector and magnetic field=90-30 =60 degree

Torque=80*8*0.12*40*10^(-3)sin(60)=2.66 Nm

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