As an intern with an engineering firm, you are asked to measure the moment of in

Question

As an intern with an engineering firm, you are asked to measure the moment of inertia of a large wheel, for rotation about an axis through its center Since you were a good physics student, you know what to do. You measure the diameter of the wheel to be 0.740 m and find that it weighs 280 N. You mount the wheel, using frictionless bearings, on a horizontal axis through the wheel's center. You wrap a light rope around the wheel and hang a 8.00-kg mass from the free end of the rope. You release the mass from rest: the mass descends and the wheel turns as the rope unwinds. You find that the mass has speed 5.00 m/s after it has descended 2.00 m What is the moment of inertia of the wheel for an axis perpendicular to the wheel at its center? Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

Explanation / Answer

Here

radius of wheel , r = 0.74/2 = 0.37 m

weight of wheel , W = 280 N

part B)

for the maximum moment of inertia of wheel having same mass and radius is

I = m * r^2

I = (280/9.8) * 0.37^2

I = 3.911 Kg.m^2

hence , as the maximum moment of inertia of wheel can be 3.911 Kg.m^2

it is NOT possible to have a wheel to have moment of inertia 19 Kg.m^2 for same mass and radius

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