A 2.84C and a -2.11 C charge are placed 4.44 cm apart. At what point along the l

Question

A 2.84C and a -2.11 C charge are placed 4.44 cm apart. At what point along the line joining them is the electric field zero? Assume that the first charge is at the origin and the second charge is at +4.44 cm. 3.22×101 cm At what points along the line joining them is the potential zero? Let V = 0 at r = infinity and enter the smaller distance first. 2.55cm Remember that electric potential is a scalar. Where will the potentials for the two oppositely charged particles sum to zero? 0cm The second part is still wrong and i wants to know why. thanks for the help.

Explanation / Answer

V will be Zero when

Vt = V1 + V2 = 0

V1 = -V2

kQ/x = Kq/(d-x)

Q/x = q/(d-x)

2.84/x = 2.11/(4.44 - x)

x = 2.55 cm

as you have to enter smaller distance first, So

V will be zero at

d1 = d - x = 4.44 - 2.55 = 1.89 cm

Answer will be 1.89 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.