A bullet of mass m1 =.050Kg strikes and passes through a wooden block whose mass

Question

A bullet of mass m1 =.050Kg strikes and passes through a wooden block whose mass is m2 = 4.0 Kg. the block is suspended vertically by a 1 m long string. The bullet emerges with a speed of 60 m/s, and the block swings through a maximum angle of 32.46 degrees. Is kinetic energy conserved in the impact? Is momentum conserved in the impact? How high is the block at the highest point? What is the velocity of the block just after the bullet passed through lit What was the initial velocity of the bullet?

Explanation / Answer

here,

m1 = 0.05 kg

m2 = 4 kg

initial speed , u = 60 m/s

theta = 32.46 degree

a)

as the collison is elastic

the kinetic energy remains conserved

b)

the momentum is also conserved in the impact

c)

let the height be h

( 1 - h)/1 = cos(theta)

h = 0.16 m

the height of block at the heighest point is 0.16 m

d)

let the velocity of block after the impact be v1

using conservation of mechanical energy

m2 * g * h = 0.5 * m2 * v^2

9.8 * 0.16 = 0.5 * v^2

v = 1.77 m/s

the velocity of the block just after the bullet passed is 1.77 m/s

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