A bullet of mass 15 g is fired with an initial speed of 309 m/s into a wooden bl

Question

A bullet of mass 15 g is fired with an initial speed of 309 m/s into a wooden block that is initially at rest. The bullet becomes lodged in the block, and the bullet and block then slide together on the floor for a distance of1.4 m before coming to rest (see figure below). If the coefficient of friction between the block and the floor is 0.40, what is the mass of the block?
kg

A bullet of mass 15 g is fired with an initial speed of 309 m/s into a wooden block that is initially at rest. The bullet becomes lodged in the block, and the bullet and block then slide together on the floor for a distance of1.4 m before coming to rest (see figure below). If the coefficient of friction between the block and the floor is 0.40, what is the mass of the block?

Explanation / Answer

acceleration due to friction=mu*g=0.4*9.8 =3.92 m/s^2

v^2=2*a*s

==> v=sqrt(2*3.92*1.4)=3.313 m/s

now using momentum balance

0.015*309=m*3.313

==> m=1.399 Kg

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