A 0.251 m -long bar moves on parallel rails that are connected through a 5.85 re
ID: 1457513 • Letter: A
Question
A 0.251 m -long bar moves on parallel rails that are connected through a 5.85 resistor, as shown in the following figure (Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform magnetic field 1.42 T that is directed into the plane of the figure.
A)At an instant when the induced current in the circuit is counterclockwise and equal to 1.84
A , what is the magnitude of the velocity of the bar?
v=?
B)What is the direction of the velocity of the bar?
Explanation / Answer
A) induced current = induced emf /R = VBL/R
=> V = (1.84*5.85)/(1.42*0.251) = 30.20 m/s
B) velocity is in right direction
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