A 0.220-kg block resting on a frictionless, horizontal surface is attached to a

Question

A 0.220-kg block resting on a frictionless, horizontal surface is attached to a spring whose force constant is 83.8 N/m as in the figure below. A horizontal force F^ vector causes the spring to stretch a distance of 5.68 cm from its equilibrium position. Find the magnitude of F^ vector. N What is the total energy stored in the system when the spring is stretched J Find the magnitude of the acceleration of the block immediately after the applied force is removed. m/s^2 Find the speed of the block when it first reaches the equilibrium position. m/s If the surface is not frictionless but the block still reaches the equilibrium position, would your answer to part (d) be larger or smaller larger smaller There is not enough information to answer. What other information would you need to know to find the actual answer to part (d) in this case What is the largest value of the coefficient of friction that would allow the block to reach the equilibrium position

Explanation / Answer

a)

F = kx = 83.8*5.68 = 475.99 N

b)

E = 0.5*kx2 = 0.5*83.8*5.68 *5.68 = 1351.8 J

c)

F = ma

a = 475.99/.22 = 2163.6 m/s2

d)

1351.8 = 0.5*mv2

v = sqrt(1351.8 *2/.22) = 110.86 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.