A 8.10 × 103-kg car is travelling at 28.7 m/s when the driver decides to exit th

Question

A 8.10 × 103-kg car is travelling at 28.7 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 369 m along the exit ramp the car's speed is 12.9 m/s, and it is h = 11.9 m above the freeway. What is the magnitude of the average drag force exerted on the car?

Nate the Skate was an avid physics student whose main non-physics interest in life was high-speed skateboarding. In particular, Nate would often don a protective suit of Bounce-Tex, which he invented, and after working up a high speed on his skateboard, would collide with some object. In this way, he got a gut feel for the physical properties of collisions and succeeded in combining his two passions.* On one occasion, the Skate, with a mass of 119 kg, including his armor, hurled himself against a 847-kg stationary statue of Isaac Newton in a perfectly elastic linear collision. As a result, Isaac started moving at 1.77 m/s and Nate bounced backward. What were Nate's speeds immediately before and after the collision? (Enter positive numbers.) Ignore friction with the ground. Before:

Explanation / Answer

A 8.10 × 103-kg car is travelling at 28.7 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 369 m along the exit ramp the car's speed is 12.9 m/s, and it is h = 11.9 m above the freeway. What is the magnitude of the average drag force exerted on the car?

Mass of Car = 8.10 * 10^-3 Kg
Speed of Car = 28.7 m/s

Initial Energy = 0.5*m*v^2
Initial Energy = 0.5*8.1*10^3 * 28.7^2 J
Initial Energy = 3.33 * 10^6 J

Final Energy = 0.5*m*v^2 + m*g*h
Final Energy = 0.5*8.1*10^3 * 12.9^2 + 8.1*10^3 *9.8*11.9 J
Final Energy = 1.618 * 10^6 J

Drag Force = Loss in Energy / Distance Moved
Drag Force = (3.33 * 10^6 - 1.618 * 10^6) / 369
Drag Force = 4639.56 N


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