A block is attached to a spring and set in motion on a horizontal frictionless s

Question

A block is attached to a spring and set in motion on a horizontal frictionless surface by pulling the block back a distance 10cm from equilibrium. Now, replace the block with one double the mass and set the block into motion again by pulling the block a distance 10cm from equilibrium and releasing. How will the following new quantities relate to the quanities with the original block? (If it will be larger by a factor of 2, choose double. sqrt stands for square root.)

-Frequency of oscillation

-Amplitude Maximum

-Force of the Spring on the Block

-Maximum Acceleration

Explanation / Answer

frequency of oscillatio is given as

frequency = 2*pi*sqrt(k/m)

for doubling the mass ,

frequency of oscillation will be 1/sqrt(2) times

frequency of oscillation will be 0.707 times

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as the amplitude is same for both blocks

maximum amplitude is 10 cm

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as force = k * x

for same spring ,

the force will be same

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as acceleration = force/mass

for double the mass

the maximum accelration will be 1/2 times

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