A block has a volume of 0.600 m^3 and a density of 3.50x10^2 kg/m^3. The block i

Question

A block has a volume of 0.600 m^3 and a density of 3.50x10^2 kg/m^3. The block is placed into a container of water of density 1.00x10^3 kg/m^3. Determine the following: a) Determine the percentage of the block's volume that is above the water when it is placed in the container of water. b) A second block of density 4.5x10^2 kg/m^3 is placed on top of the original block. This causes the original block to be completely submerged and the second block to be 10% submerged in the water. Determine the volume of the second block Please show all steps

Explanation / Answer

equating the volumes of both after immersion 350*0.6=V*1000 V=.21 is immersed therefore % exposed =(.6-.21).6=.65 or 65 % let the second volume is k writing the equation k*450+.6*350=.6*1000+.1*k*1000 k=1.11m^3 please rate this

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