A physics lab is demonstrating the principles of simple harmonic motion (SHM) by

Question

A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal support. The student is asked to find the spring constant, k. After suspending a mass of 335.0 g from the spring, the student notices the spring is displaced 31.5 cm from its previous equilibrium. With this information, calculate the spring constant.

When the spring, with the attached 335.0-g mass, is displaced from its new equilibrium position, it undergoes SHM. Calculate the period of oscillation, T, neglecting the mass of the spring itself.

Explanation / Answer

a)

Weight of the spring =Force due to spring

mg =KX

=>K=mg/X =(0.335*9.8)/0.315

K=10.4 N/m

b)

Time period of oscillation is

T=2pi*sqrt[m/k]

T=2pi*sqrt[0.335/10.42]

T=1.126 s =1.13 s(approx)

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