In the figure, a conducting rod of length L = 35.0 cmmoves in a magnetic field B

Question

In the figure, a conducting rod of length L = 35.0 cmmoves in a magnetic field B?  of magnitude 0.400 Tdirected into the plane of the figure. The rod moves with speed v = 4.00 m/s in the direction shown. (Figure 1)

Part A

When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?

Part B

What is the direction of the electric field in the rod?

Part C

When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?

Express your answer in volts per meter to at least three significant figures.

Part D

Which point, a or b, has a higher potential?

Part E

What is the magnitude Vba of the potential difference between the ends of the rod?

Express your answer in volts to at least three significant figures.

Part F

What is the magnitude E of the motional emf induced in the rod?

Express your answer in volts to at least three significant figures.

Explanation / Answer

length of the conducting rod L=35 cm

magnetic field B=0.4T

speed of the rod v=4 m/sec

A)

point b has excess positive charge,

because,

force on charge is acting towards right side,

and positive charges will move towards point b

B)

direction of electric field is from b to a

because,

direction of electric field is from high potential to low potential

c)

electric field E=v*B

E=4*0.4

E=1.6 v/m

d)

point b is at high potential

because,

all positive charges will move towards point b

e)

vba=l*v*B

=35*10^-2*4*0.4

=0.56 v

f)

induced emf E=l*v*B

=35*10^-2*4*0.4

=0.56 v

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