In the figure, a conducting rod of length L = 35.0 cm moves in a magnetic field
ID: 1584409 • Letter: I
Question
In the figure, a conducting rod of length L = 35.0 cm moves in a magnetic field B of magnitude 0.460 T directed into the plane of the figure. The rod moves with speed v = 4.00 m/s in the direction shown.
Part C
When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?
Express your answer in volts per meter to at least three significant figures
Part E
What is the magnitude Vba of the potential difference between the ends of the rod?
Express your answer in volts to at least three significant figures.
Part F
What is the magnitude E of the motional emf induced in the rod?
Express your answer in volts to at least three significant figures.
Explanation / Answer
C) When rod is in equilibrium
qE = Bqv
Electric field
E= Bv = (0.460T) (4 m/s) = 1.84 V/m
d)
Potential difference Vba = E * L = 1.84 * 0.35 = 0.644 V
e)
motional emf E = BLv = (0.460 T) (0.35 m) (4 m/s) = 0.644 V
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.