The frequency of an electromagnetic wave A is three times higher than that of th

Question

The frequency of an electromagnetic wave A is three times higher than that of the electromagnetic wave B , I.e fa/fb=3. Both waves are traveling in vacuum. What is the ratio of their wavelengths? A.3, because wave A moves three times as fast as wave B B. 3, because wave B moves three times faster than wave A C. 1/3, because wave A moves at one third the speed B D. 1/3, because wave B moves at one third the speed A E. 1/3, because both waves have the same speed The frequency of an electromagnetic wave A is three times higher than that of the electromagnetic wave B , I.e fa/fb=3. Both waves are traveling in vacuum. What is the ratio of their wavelengths? A.3, because wave A moves three times as fast as wave B B. 3, because wave B moves three times faster than wave A C. 1/3, because wave A moves at one third the speed B D. 1/3, because wave B moves at one third the speed A E. 1/3, because both waves have the same speed A.3, because wave A moves three times as fast as wave B B. 3, because wave B moves three times faster than wave A C. 1/3, because wave A moves at one third the speed B D. 1/3, because wave B moves at one third the speed A E. 1/3, because both waves have the same speed

Explanation / Answer

the ratio of the frequencies given as fA/ fB = 3

we know that relation between wave speed , frequency, wavelength   V= lambda*f

here both waves are moving in vacuum so no chnage of medium then there is no change in the speeds of the waves

and wavelength and frequency are inversly proportional to each other in a same medium

so the ratio of their wavelengths are lambdaA / lambda B = 1/3

option E is correct answer

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