You are assigned the design of a cylindrical, pressurized water tank for a futur

Question

You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 125 kPa, and the depth of the water will be 13.9 m. The pressure of the air in the building outside the tank will be 93.0 kPa. Find the net downward force on the tank's flat bottom, of area 2.30 m^2, exerted by the water and air inside the tank and the air outside the tank. Express your answer numerically in Newtons, to three significant figures.

Explanation / Answer

A) pressure at the outside the tank Po = 93 x 10^3 Pa

pressure inside Pin = P + row*g*h = (125 x 10^3) + ( 1000 x 3.71 x 13.9)

Pin = 176569 Pa

F = ( Pin - Po) A = ( 176569 - 125000) x 2.30 = 118608.7 N

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.