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dugen.willeyplus.com Moodle2: My home Home | Chegg.com gnment FULL SCREEN PRINTER VERSION BACK NEXT Your answer is partially correct. Try again. At time t, r4.502i ( 4.50? (8.8t+6.002)gives the (8.80t+ 6.00r2) J gives the position of a 3.0 kg particle relative to the origin of an xy coordinate system is in meters and t is in seconds). (a) Find the torque acting on the particle relative to the origin at the moment 1.17 s (b) Is the magnitude of the particle's angular momentum relative to the origin increasing, decreasing, or unchanging? (a) 1 573.5 k Units N-m (b) increasing the tolerance is +/-2% SHOW HINT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM MATH HELP LINK TO TEXT dy Version 4.16.2.2 rivacy.Policy 2000-201s ohnwileyasonsLne All Rights Reserved. A Division of 2ohnwleyasons,Inc

Explanation / Answer

m = 3kg

r = 4.5t2 i - (8.8t +6t2 )j

v =dr/dt = 9ti - (8.8+12t)j

a =dv/dt = 9i - 12j

at t=1.17 s , r = 4.5(1.17) i - [8.8(1.17)t+6(1.17)2]j

r =5.265 i - 18.51 j

F = ma = 3[9i - 12j]

F =27i -36j

(a)Torque = rxF

T =[5.265 i - 18.51 j]x [27i-36j]

T = -189.54k+499.77

T =310.23 k

Torque is 310.23 N.m

(b) increasing

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