Under normal circumstances, the vitreous humor, a jelly-like substance in the ma
ID: 1463744 • Letter: U
Question
Under normal circumstances, the vitreous humor, a jelly-like substance in the main part of the eye, exerts a pressure of up to 24.0 mm of mercury that maintains the shape of the eye
If blockage of the drainage duct for aqueous humor causes this pressure to increase to about 50.0 mm of mercury, the condition is called glaucoma.What is the increase in the total force (in newtons) on the walls of the eye if the pressure increases from 24.0 mm to 50.0 mm of mercury? We can quite accurately model the eye as a sphere 2.70 cm in diameter
Explanation / Answer
we know density of mercury, rho = 13.6*10^3 kg/m^3
change in pressure = P2 - P1
= rho*g*h2 -rho*g*h1
= rho*g*(h2 - h1)
= 13.6*10^3*9.8*(50-24)*10^-3
= 3465.28 pa
radius of the eye, r = d/2
= 2.7/2
= 1.35 cm
= 0.0135 m
surface area of the sphere, A = 4*pi*r^2
= 4*pi*0.0135^2
= 0.00229 m^2
increase in the total force = (P2 - P1)*A
= 3465.28*0.00229
= 7.935 N <<<<<<<------------Answer
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