Problem 20.10 A uniform electric field with a magnitude of 5950 N/Cpoints in the
ID: 1463802 • Letter: P
Question
Problem 20.10
A uniform electric field with a magnitude of 5950 N/Cpoints in the positive x direction.
Part A
Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive x direction.
Part B
Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the negative x direction.
Part C
Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive y direction.
Express your answer using one significant figure.
Problem 20.10
A uniform electric field with a magnitude of 5950 N/Cpoints in the positive x direction.
Part A
Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive x direction.
Part B
Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the negative x direction.
Part C
Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive y direction.
Express your answer using one significant figure.
U = JExplanation / Answer
here,
electric feild , E = 5950 N/C
charge , q = 17 * 10^-6 C
distance moved , d = 5 cm
d = 0.05 m
the change in potential energy , PE = E*q*d
PE = 5950 * 0.05 * 17 * 10^-6
PE = 5.06 *10^-3 J
a) since the positive charge moved in the direction of the field the PE would decrease by 5.06 *10^-3 J
b) charge is moved 5.00 cm in the negative x direction means an increase in PE by 5.06 *10^-3 J
c) motion perpendicular to field so no change in PE
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