Problem 20.10 A uniform electric field with a magnitude of 6100N/C points in the
ID: 1272811 • Letter: P
Question
Problem 20.10
A uniform electric field with a magnitude of 6100N/C points in the positive x direction.
Part A
Find the change in electric potential energy when a +19.0-?C
charge is moved 6.50cm in the positive x direction.
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Part B
Find the change in electric potential energy when a +19.0-?C
charge is moved 6.50cm in the negative x direction.
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Part C
Find the change in electric potential energy when a +19.0-?C
charge is moved 6.50cm in the positive y direction.
Express your answer using one significant figure.
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Problem 20.10
A uniform electric field with a magnitude of 6100N/C points in the positive x direction.
Part A
Find the change in electric potential energy when a +19.0-?C
charge is moved 6.50cm in the positive x direction.
SubmitMy AnswersGive Up
Part B
Find the change in electric potential energy when a +19.0-?C
charge is moved 6.50cm in the negative x direction.
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Part C
Find the change in electric potential energy when a +19.0-?C
charge is moved 6.50cm in the positive y direction.
Express your answer using one significant figure.
?U = JSubmitMy AnswersGive Up
Explanation / Answer
Change in potentialenergy ?U = -q * ?V
= -q * E * d
here charge q = +19 ?C
Electricfield E = 6100 N/C
a. displacement d = + 6.50cm
= +0.0650 m
?U1 = -19 * 10-6 * 6100 * 0.0650
= - 7.533* 10-3 J
b. displacement d = - 6.50 cm
= -0.0650 m
?U2 = -19 * 10-6 * 6100 * (- 0.0650)
= 7.533* 10-3 J
c)
the field has no y-component, so there is 0 potential energy change.
as d =0
?U = q E (o) =0
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