Problem 20.10 A uniform electric field with a magnitude of 6250 N/C points in th

V = Ed U = VQ = EQd A. U = 6250 * 17.5 * 10-6* 6.5*10-2 = 7.11*10-3J b. U = -EQd = -7.11*10-3J c U = zero since V and E are perpendicular

ID: 1571101 • Letter: P

Question

Problem 20.10

A uniform electric field with a magnitude of 6250 N/C points in the positive x direction.

Part A

Find the change in electric potential energy when a +17.5-C
charge is moved 6.50 cm in the positive x direction.

Part B

Find the change in electric potential energy when a +17.5-C
charge is moved 6.50 cm in the negative x direction.

Part C

Find the change in electric potential energy when a +17.5-C
charge is moved 6.50 cm in the positive y direction.

Express your answer using one significant figure.

V = Ed

U = VQ = EQd

U = 6250 * 17.5 * 10-6* 6.5*10-2

= 7.11*10-3J

U = -EQd = -7.11*10-3J

U = zero since V and E are perpendicular

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