A- During a neighborhood baseball game in a vacant lot, a particularly wild hit

Question

A- During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 143-g baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 10.3 m/s, shatters the glass as it passes through, and leaves the window at 8.45 m/s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball?

1- The direction of the ball's motion

2- Opposite the direction of the ball's motion

3- Neither of these

B- Calculate the magnitude of this impulse (a positive number).

C- The ball is in contact with the glass for 10.9 ms as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number).

Explanation / Answer

A)

The direction of the impulse is directly opposite to the direction of the balls path. B)

B)

From the impulse-momentum theorem, Impulse = change in momentum

Impulse = mv

Impulse = (0.143)(8.45 – 10.3)

Impulse =-0.265 kg m/s

Magnitude of impulse is 0.265 kg m/s

C)

Impulse = Ft

0.265 kg m/s = (F)(0.0109)

F = 24.3 N

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