2.Given = 475.9[nm] and = 41.95°, then what is the index of refraction to the ne

Question

2.Given = 475.9[nm] and = 41.95°, then what is the index of refraction to the nearest hundredth?

6. How would you use the spectrometer to determine the name of an unlabeled gas while also given a known gas?
¶ < 75 words

CRC has a look-up table for finding unknown gasses. Measure 's using a spectrometer by carefully find minimum angle of deviation and then measure the bending. Use chart of known gasses.

You can't find unknown gasses using a spectrometer because we don't know the wavelengths of the unknown gas. Cauchy's Relationship requires us to know the wavelengths.

I would measure n for the unknown wavelengths. Then plot n vs. -2 and find Cauchy's relationship for the unknown gas; this would lead me to a chart of known gasses.

Using the linear equation (Cauchy's relationship) from the known gas, I would calculate the 's with the measured n's and compare these 's to known gasses until I had a match.

Explanation / Answer

To answer this, I have to make a couple of assumptions on your problem as stated.

To calculate the index of refraction, you need to have both the incident angle and resultant angle. The incident angle is the angle the light strikes the surface. The resultant angle is the angle the light takes inside the optic.

use 1 and 2. 1 is the incident angle, 2 is the resultant angle.

To find the index of refraction, you take n1/n2 = sin 2/sin 1.

Presume:
n1 = 1
1 = =60°
2 = 41.95°

Now, solve for n2.

n2 = n1(sin 1/sin 2).
= 1 (sin 60 / sin 41.95)
= .866 / .668
n2= 1.295

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