?help ASAP and make it clear please 3 THANK YOU! The figure below shows five ide
ID: 1466312 • Letter: #
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?help ASAP and make it clear please 3 THANK YOU!
The figure below shows five identical rectangular loops of wire in a uniform magnetic field that is directed into the page. Outside of the region shown, the magnetic field is zero. Loop A is getting stretched larger, while Loops B - E are moving with the same constant speed. The The figure to the left shows the initial locations of all loops and the figure to the right shows the locations of all the loops a short time later. Suppose the magnetic field remains constant as the loops move. Rank the current in each loop, greatest first. For each loop, specify whether the current is clockwise (cw), counter-clockwise (ccw), or if there is no current (none). Explain briefly. Suppose instead that the magnetic field decreases to half its original value in the time between the figures as the loops move. Rank the current in each loop, greatest first. For each loop, specify whether the current is clockwise (cw), counter-clockwise (ccw), or if there is no current (none). Explain briefly. You may consider the effect of the motion and changing magnetic field separately and then combine them. It is possible to conclusively determine the entire ranking.Explanation / Answer
3)
here , as inudced current = rate of change of flux with time/R
as rate of change of flux = B*v*L
as the rate of change of flux is maximum for A ( have both sides increasing area)
then for B (larger side moving)
then it is equal for D and E
as the flux is constant in C , there is induced current
the rank from largerst current to smallest is
A(CCW) > B (CW) > D(CCW) = E(CCW) > C(zero)
b)
if the the magnetic field also changes , as it is changing same for all the loops , this will change the rates same for all the loops ,
hence , the order will remain the same .
the direction of current it to found using Lenz's law
the flux will decrease in all the loops ( as the area increased inside the loop is less than half)
A(CW) > B (CW) > D(CW) = E(CW) > C(CW)
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