A 4.0-cm-diameter loop with resistance 0.13 Ohm around a 2.0-cm-diameter solenoi
ID: 1467105 • Letter: A
Question
A 4.0-cm-diameter loop with resistance 0.13 Ohm around a 2.0-cm-diameter solenoid. The solenoid is 11 cm long, has 100 turns, and carries the current shown in the graph. A positive current is cw when seen from the left. Find the current in the loop at t = 0.5s. Express your answer as an integer and include the appropriate units. Find the current in the loop at t = 1.5s. Express your answer to two significant figures and include the appropriate units. Find the current in the loop at t = 2.5s. Express your answer as an integer and include the appropriate units.Explanation / Answer
magnetic field in the solenoid = B = uo*n*I = uo*N/L*I
N = 100
L = 0.11 m
flux through the loop = B*A
emf induced = rate of chang ein flux
e = (d/dt)*(B*A)
A = area of cross section of loop containig flux
e = uo*N/L*A*dI/dt
current in the loop = i = e/R
i = uo*N/L*pi*r^2*dI/dt*(1/R)
A)
at t = 0.5 the current in the solenoid is not changing dI = 0
i = 0
B)
between t = 1 s to t = 1.5 s current changed from 20 A to 0 A
dI = 20
dt = 0.5
i = uo*N/L*pi*r^2*dI/dt*(1/R)
i = (4*pi*10^-7*(100/0.11)*pi*0.01^2*(20/0.5)*(1/0.13))
i = 0.00011A = 0.11 mA
__
C)
at time t = 2.5 s
the current is constant dI = 0
i = 0
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