I dont get this question at all. please answer all parts 20.0-m-long uniform bea

ID: 1467115 • Letter: I

Question

I dont get this question at all. please answer all parts

20.0-m-long uniform beam weighing 900 N rests on walls A and B, as shown in the figure (Figure 1) .

0)Find the maximum weight of a person who can walk to the extreme end D without tipping the beam.

1) Find the force that the wall A exert on the beam when the person is standing at D.

2)Find the force that the wall B exert on the beam when the person is standing at D.

3)Find the force that the wall A exert on the beam when the person is standing at a point 2.0 m to the right of B.

4)Find the force that the wall B exert on the beam when the person is standing at a point 2.0 m to the right of B.

5)Find the force that the wall A exert on the beam when the person is standing 2.0 m to the right of A.

6)Find the force that the wall B exert on the beam when the person is standing 2.0 m to the right of A.

0) before tipping, force exerted y wall is zero.

and net torque about wall B = 0

5*900 - 5*m*g = 0

==> m = 900/g

= 900/9.8

= 91.84 kg

1) zero

2) FB = 2*900

= 1800 N

3) Apply, net force about wall B = 0

900*5 - FA*12 - 900*2 = 0

FA = 900*(5-2)/12

= 225 N

4) Apply, Fnety = 0

FA + FB - 900 - 900 = 0

FB = 1800 - FA

= 1800 - 225

= 1575 N

5) Apply, net force about wall B = 0

900*5 + 900*10 - FA*12 = 0

FA = 900*(5 + 10 )/12

= 1125 N

6) Apply, Fnety = 0

FA + FB - 900 - 900 = 0

FB = 1800 - FA

= 1800 - 1125

= 675N

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