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An ice chest initially contains 4.01 kg of ice at 0°C. (a) Find the change in th

ID: 1467287 • Letter: A

Question

An ice chest initially contains 4.01 kg of ice at 0°C.

(a) Find the change in the entropy of the system of the ice chest and its contents just after the ice has melted.
J/K

(b) Find the change in the entropy of the surroundings, assuming the air outside the ice chest is at 23°C.
J/K

(c) Find the total entropy change of the universe as a result of this process.
  J/K

(d) Find the ratio f/i for the system.
exp(   )

Find the ratio f/i for the surroundings.
exp(  )

Find the ratio f/i and for the combination of the system and its surroundings.
exp(  )

Explanation / Answer

here,

a)

Entropy Change = (Energy transferred) / (Temperature in kelvin)

deltaS = Q / T


Q = (mass)(latent heat of fusion)

Q = m(hfusion)

Q = (4010g)(333J/g) = 1335330 J


T(K) = T(C) + 273.15 = 273.15K

deltaS = - 1335330 J / 273.15K

deltaS = - 4888.63 J/K

b)

temprature , T = 23 degree

T = 273 + 23 = 296 degree

change in entropy , delta S' = Q/T

delta S' = 1335330/296

delta S' = 4511.26

the change in entropy is 4511.26 J/k

c)

the total entropy change of the universe as a result of this process = delta S + delta S'

the total entropy change of the universe as a result of this process = - 4888.63 + 4511.25

= - 377.38 J/k

the total entropy change of the universe as a result of this process is - 377.38 J/k

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