An ice chest initially contains 4.01 kg of ice at 0°C. (a) Find the change in th
ID: 1467287 • Letter: A
Question
An ice chest initially contains 4.01 kg of ice at 0°C.
(a) Find the change in the entropy of the system of the ice chest and its contents just after the ice has melted.
J/K
(b) Find the change in the entropy of the surroundings, assuming the air outside the ice chest is at 23°C.
J/K
(c) Find the total entropy change of the universe as a result of this process.
J/K
(d) Find the ratio f/i for the system.
exp( )
Find the ratio f/i for the surroundings.
exp( )
Find the ratio f/i and for the combination of the system and its surroundings.
exp( )
Explanation / Answer
here,
a)
Entropy Change = (Energy transferred) / (Temperature in kelvin)
deltaS = Q / T
Q = (mass)(latent heat of fusion)
Q = m(hfusion)
Q = (4010g)(333J/g) = 1335330 J
T(K) = T(C) + 273.15 = 273.15K
deltaS = - 1335330 J / 273.15K
deltaS = - 4888.63 J/K
b)
temprature , T = 23 degree
T = 273 + 23 = 296 degree
change in entropy , delta S' = Q/T
delta S' = 1335330/296
delta S' = 4511.26
the change in entropy is 4511.26 J/k
c)
the total entropy change of the universe as a result of this process = delta S + delta S'
the total entropy change of the universe as a result of this process = - 4888.63 + 4511.25
= - 377.38 J/k
the total entropy change of the universe as a result of this process is - 377.38 J/k
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