An electric turntable 0.700 m in diameter is rotating about a fixed axis with an

Question

An electric turntable 0.700 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.280 rev/s . The angular acceleration is 0.915 rev/s2 .

NEED PART C-D

PART C:What is the tangential speed of a point on the tip of the blade at time t = 0.210 s ?

ANSWER :v= _____________m/s

PART D: What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t = 0.210s ? ANSWER: a =___________m/s^2

FYI: THESE ARE NOT THE CORRECT ANSWERS,

2 PEOPLE HAVE RESPONDED WITH THESE ANSWERS AND ARE INCORRECT

C: IS NOT 2.08 m/s

D: IS NOT 7.63 m/s^2

SO I STILL NEED THE CORRECT ANSWERS FOR PART C & D PLEASE!!!

Explanation / Answer

w1 = 0.285 rev/s

alfa = 0.915 rev/s^2

radius, r = d/2 = 0.7/2 = 0.35 m

C) at time t = 0.21 s

w2 = w1 + alfa*t

= 0.285 + 0.915*0.21

= 0.47715 rev/s

= 0.47715*2*pi rad/s

= 3 rad/s

tangential speed of a point on the tip of the blade, v2 = r*w2

= 0.35*3

= 1.05 m/s

D) a_tan = r*alfa

= 0.35*0.915*2*pi

= 2.01 m/s^2

a_rad = r*w2^2

= 0.35*3^2

= 3.15 m/s^2

a_total = sqrt(a_tan^2 + a_rad^2)

= sqrt(2.01^2 + 3.15^2)

= 3.74 m/s^2 <<<<<<<<<<<<<<<------------------------Answer

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