1. -4 points A circuit consists of a 12 V battery connected to a switch which is

Question

1. -4 points A circuit consists of a 12 V battery connected to a switch which is connected to a light bulb of resistance 120 and then back to the battery. If the switch s open, which statement is true of 1 the current through the switch) and V 0 1 0 A, V, is not zero but less than 12 V the difference in potential across the poles of the switch 0.1 A, Vs is more than 12 V 0 1-10 A, Vs = 12 V I 0.1 A, Vs is not zero but less than 12 V 0 1 = 0 A, Vs is more than 12 V 0 1-0.1 A, V,-12 V O ! 10 A, V, is not zero but less than 12 V 0 1 10 A, V, is more than 12 V b) A long wire (with measurable resistance) is connected to a battery of potential difference V, and current I flows through the wire. The voltage is now doubled, but a fan keeps the the temperature of the wire from increasing. What will happen to the current I and the resistivity of the wire p? 0 1 will double, will halve 0 1 will halve, will quadruple 0 1 will remain the same, will double 0 1 will remain the same, will halve I will double, will quadruple 0 I will halve, will double I will double, will remain the same I will remain the same, will quadruple 0 1 will remain the same, will be quartered 0 1 will halve, will remain the same 0 1 will remain the same, will remain the same 0 1 will halve, will halve 0 1 will double, will be quartered 0 1 will halve, will be quartered I will double, will double

Explanation / Answer

a) I= 0 , Vs= 12 V

no current will flow throuh open switch and potential will develop of the battery =12 V

b) when potential is V current is I

when potential is doubled the resistance is same so the current will double, the resistivity will remain constant as the material is prevented from heating up

so answer is I will double , rho will remain same

c)as new wire is increased so current will decrease due to increase in R

now the same voltage will be divided across 8 wires so voltage will reduce too.

so answer is bith V1 and I1 will decrease.

d)now this is a parallel connection , so potential will be constant across all wires ,

but an extra wire will need current so I1 will decrease.

so anser is V1 will remain constant and I1 will decrese

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