a) In procedure 1 you will use a laser box. This is a can harm you only if the l

Question

a) In procedure 1 you will use a laser box. This is a can harm you

only if the laser light hits your skin directly

if the leaser beam hits your skin, either directly or by reflection    

if the laser light goes into your eye, either directly or by reflection

only if the laser light goes directly into your eye

f1 will increase, f2 will decrease

f1 will decrease, f2 will increase    

f1 will remain the same, f2 will increase

f1 will decrease, f2 will remain the same

f1 will decrease, f2 will decrease

f1 will increase, f2 will increase

f1 will remain the same, f2 will decrease

f1 will increase, f2 will remain the same

f1 will remain the same, f2 will remain the same

c) In procedure 1: the laser box is placed 14.1 cm from the convex lens, and you find the focal length of the lens is 9.14 cm. If the distance from the lens to the laser box is now 20.2 cm, , the focal length of the lens will now be____________cm

d) Suppose you pass light through a concave lens and convex lens, both made of glass (n = 1.50) and find that the magnitude of their focal lengths are both f. If the measurement is now done underwater (n = 1.33) instead of in an air atmosphere

concave: exactly f, convex: more than f

concave: exactly f, convex: exactly f    

concave: exactly f, convex: less than f

concave: less than f, convex: less than f

concave: less than f, convex: more than f

concave: more than f, convex: more than f

concave: more than f, convex: exactly f

concave: less than f, convex: exactly f

concave: more than f, convex: less than f

d) An object is placed just slightly less than f from a convex lens, and now you move the object toward the lens. What happens to the virtual image?

the image remains the same size, and moves farther from the lens

the image grows larger, and moves closer to the lens    

the image grows larger, and moves farther from the lens

the image grows smaller, and remains fixed

the image grows smaller, and moves farther from the lens

the image grows smaller, and moves closer to the lens

the image remains the same size, and remains fixed

the image remains the same size, and moves closer to the lens

the image grows larger, and remains fixed

e) An object is placed just slightly less than f from a concave lens, and now you move the object toward the lens. What happens to the virtual image?

the image grows larger, and moves closer to the lens

the image remains the same size, and remains fixed    

the image grows smaller, and remains fixed

the image grows smaller, and moves farther from the lens

the image grows larger, and moves farther from the lens

the image grows larger, and remains fixed

the image remains the same size, and moves farther from the lens

the image remains the same size, and moves closer to the lens

the image grows smaller, and moves closer to the lens

In procedure 2, suppose the convex lens is placed at the 48.6 cm mark, and an image forms on the screen at the 76.1 cm mark. Find:

- the focal length of this lens__________cm
- the absolute value of the magnification of this lens ___________
- the height of the image___________cm

Explanation / Answer

a) if light goes into your eyes directly.

b) f1 decreses and f2 remains the same

c) focal length will remain same = 9.14 cm

d) concave: more than f, convex: more than f

d) the image grows smaller, and moves closer to the lens

e) the image grows larger, and moves closer to the lens

f = 29.66 cm using the formula 1/f = 1/v -1/u

magnification = v/u = -76.1/48.6 = 1.566

height of image can only be find if size of object is given using image = object x magnification

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