a) In point A the I-beam support has pin support. In part B the I beam has a rol
ID: 1821655 • Letter: A
Question
a) In point A the I-beam support has pin support. In part B the I beam has a roller support. Determine the reaction at this supports. I know there in 1 reaction at pt. B (upwards) and 2 reactions at pint A (upwards, and horizontal). My teacher gave us the answers, but I dont understand why they are in terms of N and not kg, cus I keep getting Kg.
Answers Fax= 0N (force on A in the x direction) Fay = 647.5N (Force on a in the y direction) Fb=1510.7N (force on b)
b) In this diagram, I am just not sure if how many forces the body free diagram should contain. The problem states the beam 18kg, but so far we have not included the weight of the objects in any of our work. AB is a cable supporting the I- beam, and their is a pin support at pt. O. Calculate the tension in the cable and the pin reaction at O.
Answer Tension = 99.5N Rox = 82.8N Roy = 231.8N
a) In point A the I-beam support has pin support. In part B the I beam has a roller support. Determine the reaction at this supports. I know there in 1 reaction at pt. B (upwards) and 2 reactions at pint A (upwards, and horizontal). My teacher gave us the answers, but I dont understand why they are in terms of N and not kg, cus I keep getting Kg. Answers Fax= 0N (force on A in the x direction) Fay = 647.5N (Force on a in the y direction) Fb=1510.7N (force on b) b) In this diagram, I am just not sure if how many forces the body free diagram should contain. The problem states the beam 18kg, but so far we have not included the weight of the objects in any of our work. AB is a cable supporting the I- beam, and their is a pin support at pt. O. Calculate the tension in the cable and the pin reaction at O. Answer Tension = 99.5N Rox = 82.8N Roy = 231.8NExplanation / Answer
a) kg is the unit of mass and Newton (N) is the unit of force
here we deal with forces acting on body and since we in american context use lb as the unit of force it is a bit confusing. don't worry about it. just deal with force unit
since given that body is of 220 kg thus gravity force would be = 220 * 9.8 = 2156
so force balance in y direction gives
Fay + Fby = 2156 ..............(1)
and since there is no horizontal force thus zero reaction force on the bar
now equating the moment generated at the center of mass
Fay * 5.6 = Fby * 2.4 ...........(2)
from 1 and 2 equations
we get
Fay = 647.5 N Fby = 1510.7 N
(b)plz make it a seperate question
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