Four point charges of equal magnitude are arranged at the corners of a square. T

Question

Four point charges of equal magnitude are arranged at the corners of a square. The top left and bottom right point charge are negative (-) and the top right and bottom left point charges are positive (+). What is the direction of the electric field at a point located along the left side of the square, exactly half way between the top left negative charge and the bottom left positive charge?

(-).....................(+)
...........................
b.........................
...........................
(+)....................(-)

A) Up (to the top of the page).

B) To the left.

C) Down (to the bottom of the page)

D) To the right.

E) The electric field is zero at this point.

**PLEASE EXPLAIN WHY***

Explanation / Answer

A) Up (to the top of the page).

as field due to left two chrges are upward and distance between charges and b point is less field intensity is more

and field due to right charges is downward as distance betweeen charges and b is very high intensity of field is less

So net field will be in uward direction at b

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