A thermodynamic system goes from state A to B to C. Q A--B , is positive, and U

Question

A thermodynamic system goes from state A to B to C. QA--B, is positive, and UB--C is positive. (Select Zero, Positive, or Negative for all selections)

Positive, or Negative for all selections)

(Zero Positive Negative) WC--A
(Zero Positive Negative) UC--A
(Zero Positive Negative) WA--B
(Zero Positive Negative) QC--A
(Zero Positive Negative) UA--B
(Zero Positive Negative) WB--C
(Zero Positive Negative) QB--C

Positive, or Negative for all selections)

(Zero Positive Negative) WC--A
(Zero Positive Negative) UC--A
(Zero Positive Negative) WA--B
(Zero Positive Negative) QC--A
(Zero Positive Negative) UA--B
(Zero Positive Negative) WB--C
(Zero Positive Negative) QB--C

Explanation / Answer

WC--A is negative becausework done on the gas so the gas is contracting

UC--A is negative because internal energy is zero in cyclic process and both UA--B and UB--C are positive

(UC--A+ UA--B+ UB--C=0) implies UA-B + U B-C = - UC-A

WA--B is zero because volume of the gas constant w = p dev = p 0 = 0

QC--A is negative since UC--A and WC--A are both negative

UA-B is positive since QA--B is positive and WA--B is zero

Q AB = WAB + UA- B

WB--C is positive because work done by the gas so the gas is expanding

QB--C is positive since it is the sum of  WB--C and UB--C, both of which are positive

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